Hi my name is Rob Burchett. I have been tutoring Math, Physics and Chemistry in York Region and Toronto for over 15 years. I can tutor in person or online. I usually find a combination of these two works best. Currently, I am tutoring in person at the Thornhill Community Centre Library in Thornhill, Ontario. Now, I have two students in grade 12 Calculus, a grade 10 Math and grade 5 English and Math student. You can find some information in regards to my tutoring at the left under the category: Tutoring.

I’ve had a lot of success tutoring many students over the years. In some cases I have been able to take students who are failing and raise their grades into the 90’s. I have tutored regular high school students, gifted students, students with learning disabilities and adult students. I can tutor a student as he is taking a course or plan ahead of time for a course he is going to take.

My usual fee is $20/hr. I would be happy to provide references. I can be reached by phone or text message at 647-218-1407 or by email at robburchett1@gmail.com.

I apologize for the current construction going on at my website and hope to have it back to normal shortly.

I am seeing three students of my own this semester. A grade 5 student for Math and English, with my wife Angela. Also, I am seeing his brother, a grade 11 student who is taking calculus ahead of time. I saw him last year for grade 11 and grade 12 Math also for grade 10 English, Civics and Religion. He is doing very well.

I also see in person a student in person and online who is taking grade 10 math. I helped prepare him for this semester, one semester back. He is getting 90% in Math now. The plan is to see him in the summer months for both Math and English.

I have two students through Brainiacs Online, a grade 9 student and a grade 12 student. I am preparing the grade 12 student for Advanced Functions and also Calculus and Vectors for next semester.

I am working with my own students, tutoring grade 10 and 11 Math in person and online. I also tutor online with Brainiacs Online, online tutoring grade 10, 11 Math and grade 11 Physics. I am looking for new students in grade 9,10 or 11 Math and Physics.

It seems to me there may be an easier way to express the zeta function: Z(s)=1/1^s+1/2^s+1/3^s…..using the ideas of concept sharing as it applies to geometry.

One may imagine a type of gird with the first square being 1, the next being 1/2^2 the next being 1/3^2… if we use s=2 as an example. See pictures in the note below. The higher numbers of s can be seen by increasing the dimension.

Since with concept sharing geometry there comes a place of places, in which places can vary, we may vary the distance as we choose to always make the zeta function defined. Then there is no longer a need for analytic continuation.

Then we have that there are two types of number involved. A real part and an imaginary part.

I think this can be seen more primitively as a numbers with a fixed zero and numbers with a moving zero. The fixed number must come first, so this can be akin to the real numbers and the moving number, the moving zero, is akin to the imaginary numbers.

Then it comes about that there is a line formed in the real part with a definite center which is clearly 1/2 of the whole and the imaginary part can be any imaginary number that we choose.

As a basic introduction to a new geometry, consider two points existing together but not forming one point. This must be somehow possible as a point with no extent combined with another point of no extent will still have no extent, but there could be two points here. We have to introduce another level to geometry, since I have to take out the point that already exists in order to have this “sharing”. This means another level to space must exist. We also have to alter the idea of the number two as well. Do this we need to take the ideas of numbers and points and alter them (through “concept sharing”). I think these ideas are 17th century assessible. It may be that they were lost. See below for more details:

Now the statement of Wile’s theorem is that the sum of two squares can equal a square, but the sum of two cubes or any higher power cannot equal a single cube, a fourth power or higher. It seems then that it should be possible to demonstrate this with geometry. This new geometry mentioned above is a possible way of demonstrating this.

Let’s start by going two steps back and considering an origin which may consist of an infinite number of these new points. Then bring a line segment out into two directions along a line. We restrict the space in order to do this, taking advantage of a line of places of places (where the places can move out into )and an area of places of places of places (where the places cannot go). It can have two integer lengths, yet a single length of lengths. Since length is not the same in the new geometry. It’s length of length might be one unit, but it’s lengths can be three or four units, for example. Then let one line segment, consisting of places and place of places be moved apart in the space of places of places of places. It has a fixed length of length so the only way we can extend it is by duplication and then movement. It is placed one after the other. Then this is the demonstration that a+b=c is possible for some cases of a, b and c.

Now we move to the next dimension and consider a square, the side length of which is again two possible integers. Let there be two sets of two squares making up the initial square. This is possible since we can have half points as well. If we use the same pattern as the case of one dimension this is the demonstration that a^2+b^2=c^2 is possible for some values of a, b and c. See the diagram below.

In three dimensions and higher this is not possible to do. In three dimensions I create six cubes instead of the required eight. Also see the sketch below. This shows the proof of Wile’s theorem (Fermat’s conjecture).